Skip to content
Question 89 of 99

Q.Find dfdf for f(x)=x2+3xf(x)=x^2+3x and evaluate it for x=3x=3 and dx=0.02dx=0.02.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2024Subjective· 2mImportance★★★★★
90% · 89/99 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Computes f′(x)f'(x), evaluates it at x=3x=3, and multiplies by the given dxdx.

  1. f(x)=x2+3x⇒f′(x)=2x+3f(x)=x^2+3x\Rightarrow f'(x)=2x+3, so df=f′(x) dx=(2x+3) dxdf=f'(x)\,dx=(2x+3)\,dx. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.