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Mathematics · Ch 4 — Inverse Trigonometric Functions

The Graph of Tangent Function

4.5.1

The Graph of Tangent Function

Because the graph of y=tan⁡xy=\tan x is useful for reading off values over its repeated period, and tangent is ODD (so its graph is symmetric about the origin) with the SHORT period π\pi, it suffices to work out its shape on ONE interval of length π\pi — take (−π2,π2)\left(-\tfrac{\pi}2,\tfrac{\pi}2\right).

Table of values:

xx (rad)−π3-\tfrac{\pi}3−π4-\tfrac{\pi}4−π6-\tfrac{\pi}600π6\tfrac{\pi}6π4\tfrac{\pi}4π3\tfrac{\pi}3
tan⁡x\tan x−3-\sqrt3−1-1−13-\tfrac1{\sqrt3}0013\tfrac1{\sqrt3}113\sqrt3

Plotting and joining these gives Fig. 4.15: as xx approaches π2\tfrac{\pi}2 from below, sin⁡x→1\sin x\to1 while cos⁡x→0+\cos x\to0^+, so sin⁡xcos⁡x→+∞\tfrac{\sin x}{\cos x}\to+\infty — the vertical line x=π2x=\tfrac{\pi}2 is a vertical asymptote. Symmetrically, as x→−π2x\to-\tfrac{\pi}2 from above, tan⁡x→−∞\tan x\to-\infty, so x=−π2x=-\tfrac{\pi}2 is also an asymptote. (−π2,π2)\left(-\tfrac{\pi}2,\tfrac{\pi}2\right) is called the principal domain of tangent. …

Figure 4.15Fig. 4.15 - Graph of y = tan x on the open interval (-pi/2, pi/2), an increasing curve through the origin with vertical asymptotes at x = -pi/2 and x = pi/2.
Fig. 4.15 — Fig. 4.15 - Graph of y = tan x on the open interval (-pi/2, pi/2), an increasing curve through the origin with vertical asymptotes at x = -pi/2 and x = pi/2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. A single steeply rising S-curve through the origin, flanked by two dashed vertical asymptotes at x=−π/2x=-\pi/2 and x=π/2x=\pi/2 that the curve approaches but never touches. …

Figure 4.16Graph of y = tan x over its entire domain, showing the infinitely many increasing branches between consecutive vertical asymptotes x = (2n+1)pi/2.
Fig. 4.16 — Graph of y = tan x over its entire domain, showing the infinitely many increasing branches between consecutive vertical asymptotes x = (2n+1)pi/2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. The Fig. 4.15 branch repeated at every interval of length π\pi, each copy separated by its own pair of vertical asymptotes. …