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Exercise 11.6 · Q18

Q.Let XX have a Bernoulli distribution with mean 0.40.4. Then the variance of (2X−3)(2X-3) is

(1) 0.240.24
(2) 0.480.48
(3) 0.60.6
(4) 0.960.96.
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For a Bernoulli variable, variance is pqpq; apply the scaling law V(aX+b)=a2V(X)V(aX+b)=a^2V(X) with a=2a=2 (the constant −3-3 contributes nothing to variance).

Step 1. Bernoulli variance. With mean p=0.4p=0.4, q=1−p=0.6q=1-p=0.6: V(X)=pq=0.4×0.6=0.24V(X)=pq=0.4\times0.6=0.24. …

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