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Exercise 11.6 · Q20

Q.A computer salesperson knows from past experience that he sells a computer to one in every twenty customers who enter the showroom. What is the probability that he will sell a computer to exactly two of the next three customers?

(1) 57203\dfrac{57}{20^3}
(2) 57202\dfrac{57}{20^2}
(3) 193203\dfrac{19^3}{20^3}
(4) 5720\dfrac{57}{20}.
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Selling to 11 in 2020 customers gives p=120p=\tfrac1{20}; over the next 33 independent customers, X∼B(3,120)X\sim B(3,\tfrac1{20}), so substitute k=2k=2 into the binomial pmf.

Step 1. Identify the distribution. n=3, p=120, q=1920n=3,\ p=\dfrac1{20},\ q=\dfrac{19}{20}; X∼B ⁣(3,120)X\sim B\!\left(3,\dfrac1{20}\right). …

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