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Exercise 5.5 · Q4

Q.An engineer designs a satellite dish with a parabolic cross section. The dish is 5 m5\,\text m wide at the opening, and the focus is placed 1.2 m1.2\,\text m from the vertex

(a) Position a coordinate system with the origin at the vertex and the xx-axis on the parabola's axis of symmetry and find an equation of the parabola.
(b) Find the depth of the satellite dish at the vertex.
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The focus distance IS aa; then use half the dish's width as the yy-coordinate at the rim to find how far along the axis (the depth) the rim sits.

Step 1. Set up (part a). Vertex at origin, axis of symmetry =x=x-axis, opening right (towards the dish's opening): y2=4axy^2=4ax. Focus 1.2 m1.2\,\text m from the vertex ⇒a=1.2\Rightarrow a=1.2. Equation: y2=4(1.2)x=4.8xy^2=4(1.2)x=4.8x.

Step 2. Set up the rim point (part b). Dish is 5 m5\,\text m wide at the opening, so the rim's yy-coordinate is ±2.5\pm2.5 (half the width). …

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