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Question 84 of 126

Q.The ceiling in a hallway 20 ft wide is in the shape of a semi ellipse and 18 ft high at the centre. Find the height of the ceiling 4 feet from either wall if the height of the side walls is 12 ft.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2017Subjective· 10mImportance★★★★★
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Set up the semi-ellipse with its major axis along the 20 ft width and its extra rise (above the 12 ft walls) as the semi-minor axis, then evaluate the ellipse equation 4 ft in from a wall.

  1. Set up coordinates. Take the origin at the midpoint of the floor level directly below the centre of the ceiling, with xx measured horizontally across the 20 ft width and yy measured vertically above the top of the side walls (i.e. above height 12 ft). The hallway is 20 ft wide, so the semi-ellipse spans x=−10x=-10 to x=10x=10; thus the semi-major axis is a=10a=10.

  2. Find the semi-minor axis. The ceiling is 18 ft high at the centre and the side walls are 12 ft high, so the ellipse's extra rise above the wall level at the centre is b=18−12=6b = 18-12 = 6 ft. The cross-section of the ceiling (relative to the wall-top level) satisfies

    x2a2+y2b2=1  ⟹  x2100+y236=1.\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 \implies \frac{x^2}{100}+\frac{y^2}{36}=1.

  3. Locate the point 4 ft from a wall. A wall is at x=10x=10 (or x=−10x=-10); a point 4 ft from that wall is at x=10−4=6x = 10-4 = 6.

  4. Solve for yy at x=6x=6. …

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