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Question 81 of 127

Q.A reactor is developing energy at the rate of 32 MW. Calculate the required number of fissions per second of 92U235{}_{92}U^{235}. Assume that energy per fission is 200 MeV.

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2017Subjective· 5mImportance★★★★★
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Dividing the reactor's power output by the energy released in a single fission gives the number of fission events needed per second, which works out to 1×10181\times10^{18} fissions/s.

Given data

  • Power developed by the reactor, P=32 MW=32×106 W=3.2×107 WP=32\,MW=32\times10^6\,W=3.2\times10^7\,W (i.e. 3.2×1073.2\times10^7 joules of energy released every second)
  • Energy released per fission of 92U235_{92}U^{235}, Ef=200 MeVE_f=200\,MeV

Converting the energy per fission to joules

Using 1 eV=1.6×10−19 J1\,eV=1.6\times10^{-19}\,J:

Ef=200 MeV=200×106 eV×1.6×10−19 J/eVE_f=200\,MeV=200\times10^6\,eV\times1.6\times10^{-19}\,J/eV

Ef=200×1.6×10−13 J=3.2×10−11 JE_f=200\times1.6\times10^{-13}\,J=3.2\times10^{-11}\,J

Finding the number of fissions per second

Since the reactor's power output is the total energy released per second, and each fission releases EfE_f joules, the number of fissions occurring each second, nn, satisfies

P=n×EfP=n\times E_f

n=PEf=3.2×1073.2×10−11n=\frac{P}{E_f}=\frac{3.2\times10^7}{3.2\times10^{-11}}

n=1×1018 fissions per secondn=1\times10^{18}\,\text{fissions per second}

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