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Exercises · 8.9

Q.Assuming that the energy released by the fission of a single 92235U^{235}_{92}\text{U} nucleus is 200 MeV, calculate the number of fissions per second required to produce 1 watt of power.

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Step 1. A power of 1 watt means 1 joule of energy is required per second.

Step 2. Converting to MeV using 1 MeV=1.6×10−131\ \text{MeV}=1.6\times10^{-13} J:

1 J/s=11.6×10−13 MeV/s≈6.25×1012 MeV/s1\ \text{J/s}=\frac{1}{1.6\times10^{-13}}\ \text{MeV/s}\approx6.25\times10^{12}\ \text{MeV/s}

Step 3. Since each fission event releases 200 MeV, the number of fissions needed per second is

6.25×1012200≈3.125×1010 fissions/s\frac{6.25\times10^{12}}{200}\approx3.125\times10^{10}\ \text{fissions/s} …

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