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IV. Numerical problems · Q7

Q.When a light of frequency 9×10149 \times 10^{14} Hz is incident on a metal surface, photoelectrons are emitted with a maximum speed of 8×105 m s−18 \times 10^{5}\ \text{m s}^{-1}. Determine the threshold frequency of the surface.

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Step 1. The photoelectrons' maximum kinetic energy is Kmax=12mvmax2=12(9.1×10−31)(8×105)2≈2.912×10−19 JK_{max}=\tfrac12mv_{max}^2=\tfrac12(9.1\times10^{-31})(8\times10^{5})^2\approx2.912\times10^{-19}\ \text{J}.

Step 2. From Einstein's equation, hν=hν0+Kmaxh\nu=h\nu_0+K_{max}, so ν0=ν−Kmaxh\nu_0=\nu-\dfrac{K_{max}}{h}. …

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