Physics · Ch 4 — Electromagnetic Induction and Alternating Current
AC Circuit Containing a Pure Resistor
AC Circuit Containing a Pure Resistor
Consider a circuit containing a pure resistor of resistance R connected directly across an alternating voltage source . The resulting current i develops a potential drop across R, and Kirchhoff's loop rule (the algebraic sum of potential differences around any closed loop is zero) gives . Combining equations (4.37) and (4.38), , so
where is the peak current in the circuit. Comparing this directly with the applied voltage , the applied voltage and the resulting current are found to be exactly IN PHASE with each other in a purely resistive circuit -- they reach their positive maxima simultaneously, cross zero simultaneously, and reach their negative minima simultaneously, throughout every cycle. On a phasor diagram, this means the voltage phasor (length ) and the current phasor (length ) point in exactly the same direction at ev …
What this figure shows. A pure resistor R is connected directly across an alternating source labelled , drawn as a simple single-loop circuit with no other components present. The figure sets up the basic circuit whose Kirchhoff's-law analysis -- , so -- shows that in a purely resistive AC circuit the current is a scaled-down (by 1/R), but otherwise perfectly IN-STEP …
What this figure shows. Voltage phasor (length ) and current phasor (length ) are drawn overlapping along the SAME direction from the origin (zero angle between them), alongside matching sine-wave graphs of v and i that rise, peak, fall and cross zero at exactly the same instants as each other. The figure is the direct visual statement of the resistive circuit's key result: with no phase angle separating them, voltage and current in a purely resistive AC circuit reach their maxima together, cross zero together, and reach their minima together, througho …