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Q.How fast would a rocket have to go relative to an observer for its length to be corrected to 99% of its length at rest ? (c=3×108c = 3\times10^8 ms−1^{-1})

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2018Subjective· 5mImportance★★★★★
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Apply the relativistic length-contraction formula and solve for the speed at which the observed length is 99% of the rest (proper) length.

  1. Length contraction formula: L=L01−v2c2L = L_0\sqrt{1-\dfrac{v^2}{c^2}}, where L0L_0 is the proper (rest) length and LL is the length measured by the moving observer's frame.
  2. Given L=0.99L0L = 0.99 L_0, so 1−v2c2=0.99\sqrt{1-\dfrac{v^2}{c^2}} = 0.99.
  3. Squaring both sides: 1−v2c2=0.9801⇒v2c2=0.01991 - \dfrac{v^2}{c^2} = 0.9801 \Rightarrow \dfrac{v^2}{c^2} = 0.0199.
  4. vc=0.0199≈0.1411\dfrac{v}{c} = \sqrt{0.0199} \approx 0.1411. …

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