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Worked Examples · Example 14

Q.For the same continuous distribution (Example 13), calculate the standard deviation by the assumed mean method, taking the assumed mean as 40.

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With A=40A = 40: ∑fd=20\sum fd = 20, ∑fd2=11800\sum fd^2 = 11800, so σ=295−0.25=294.75=17.168\sigma = \sqrt{295 - 0.25} = \sqrt{294.75} = 17.168.

Working table (with d=m−Ad = m - A, A=40A = 40).

C.I.fmd = m − 40fdfd²
10–20515−25−1253125
20–30825−15−1201800
30–501640000
50–70860+201603200
70–80375+351053675

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