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Worked Examples · Example 3

Q.Calculate the mean deviation (from the mean) of the following values: 2, 4, 7, 8 and 9.

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Mean =6= 6, ∑∣d∣=12\sum |d| = 12, so M.D.=125=2.4M.D. = \dfrac{12}{5} = 2.4.

Step 1 — Arithmetic mean.

Xˉ=∑Xn=2+4+7+8+95=305=6\bar{X} = \dfrac{\sum X}{n} = \dfrac{2 + 4 + 7 + 8 + 9}{5} = \dfrac{30}{5} = 6

Step 2 — Absolute deviations from the mean (all deviations taken positive).

X|d| = |X − 6|
24
42
71
82
93
Total12

Step 3 — Mean deviation.

M.D.=∑∣d∣n=125=2.4M.D. = \dfrac{\sum |d|}{n} = \dfrac{12}{5} = 2.4

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