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Q.State Graham's law of diffusion.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2018Subjective· 2mImportance★★★★★
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Graham's law relates a gas's diffusion rate to its molar mass — lighter gases diffuse faster.

Statement: Under similar conditions of temperature and pressure, the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molar mass (or vapour density).

Mathematical form:

r∝1Mr \propto \frac{1}{\sqrt{M}}

For two gases 1 and 2 diffusing under the same conditions:

r1r2=M2M1=d2d1\frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}} = \sqrt{\frac{d_2}{d_1}}

where dd is vapour density (since M=2dM = 2d).

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