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Q.Deduce Boyle's and Graham's laws from kinetic gas equation.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2020Subjective· 4mImportance★★★★★
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Both Boyle's law (PV = constant at fixed T) and Graham's law (rate of diffusion ∝ 1/√molar mass) follow directly from the kinetic gas equation PV = (1/3)mNu²rms once temperature is held fixed.

The kinetic gas equation for n molecules of mass m each, with root-mean-square speed urmsu_{rms}, occupying volume V at pressure P is:

PV=13mNurms2PV = \tfrac{1}{3}mNu_{rms}^2

  1. Derivation of Boyle's Law: The average kinetic energy of a gas molecule is directly proportional to the absolute temperature: 12murms2∝T\tfrac{1}{2}mu_{rms}^2 \propto T So, at a constant temperature T, for a fixed amount of gas (fixed m and N), urms2u_{rms}^2 is also constant. Substituting into the kinetic gas equation, since mm, NN, and urms2u_{rms}^2 are all constant at fixed T: PV=13mNurms2=constantPV = \tfrac{1}{3}mNu_{rms}^2 = \text{constant} This is exactly Boyle's Law: at constant temperature, the pressure of a fixed mass of gas is inversely proportional to its volume (P∝1/VP \propto 1/V).
  2. Derivation of Graham's Law of Diffusion: From the kinetic gas equation, for one mole of gas (N = Avogadro number, mN = molar mass M): PV=13Murms2  ⇒  urms=3PVM=3RTMPV = \tfrac{1}{3}Mu_{rms}^2 \;\Rightarrow\; u_{rms} = \sqrt{\frac{3PV}{M}} = \sqrt{\frac{3RT}{M}} The rate of diffusion (or effusion) of a gas, rr, is proportional to the average/rms speed of its molecules: …

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