Skip to content
Question of 28

Q.Deduce

(a) Boyle's law and
(b) Charle's law from Kinetic gas equation.
Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2022Subjective· 4mImportance★★★★★
0% · 0/28 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Both Boyle's and Charles's laws follow directly from the kinetic gas equation PV = ⅓Mu² once you use the fact that the average kinetic energy of gas molecules is proportional to absolute temperature.

Kinetic gas equation: PV = ⅓Mu², where P = pressure, V = volume, M = total mass of gas (or molar mass for 1 mole), and u² = mean square speed of the molecules (u_rms² = mean of the squares of individual molecular speeds).

A key postulate of kinetic theory is that the average kinetic energy of gas molecules (½Mu² for one mole) is directly proportional to the absolute temperature T of the gas: ½Mu² ∝ T, i.e. Mu² = kT for some constant k (for a fixed amount/type of gas).

  1. Derivation of Boyle's Law (P ∝ 1/V at constant T, fixed mass of gas): From PV = ⅓Mu², rearrange: PV = ⅓(Mu²) At constant temperature T, since Mu² ∝ T, the quantity Mu² is CONSTANT for a fixed amount of gas at constant T. Therefore, PV = ⅓ × (a constant) = a constant. So, at constant temperature, PV = constant, i.e. P ∝ 1/V — this is exactly Boyle's Law.
  2. Derivation of Charles's Law (V ∝ T at constant P, fixed mass of gas): …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.