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Q.Deduce

(a) Boyle's law and
(b) Charles' law from Kinetic Gas Equation.
Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2026Subjective· 4mImportance★★★★★
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Using the kinetic gas equation PV = (1/3)mNc-bar^2 = (2/3)(KE), Boyle's law follows at constant temperature and Charles' law follows at constant pressure.

Kinetic gas equation: For n molecules (mass m each) of a gas moving with root-mean-square speed c-bar in volume V:

PV = (1/3) m N c-bar^2

Since the average kinetic energy of the molecules is proportional to the absolute temperature, we can write (1/2) m c-bar^2 proportional to T, so the total kinetic energy (KE) is proportional to T. Rearranging the kinetic gas equation:

PV = (2/3) x (1/2 m N c-bar^2) = (2/3) x (total kinetic energy) = (2/3) KE

Since KE is proportional to T, we can write PV = k T (where k is a constant for a fixed amount of gas).

(a) Boyle's law (T constant):

At constant temperature, KE is constant, so from PV = (2/3) KE:

PV = constant

i.e. at constant temperature, the volume of a fixed mass of gas is inversely proportional to its pressure (V proportional to 1/P). This is Boyle's law.

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