Skip to content
Question of 28

Q.Calculate the ratio of kinetic energies of 3 gm of hydrogen and 4 gm of oxygen at a given temperature.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2020Subjective· 2mImportance★★★★★
0% · 0/28 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Total kinetic energy of an ideal gas depends only on the number of moles and temperature (KE = 3/2 nRT), not on molar mass — so we compare moles of each gas, giving a ratio of 12:1.

Key idea: For an ideal gas, the total translational kinetic energy of n moles at temperature T is

KE=32nRTKE = \tfrac{3}{2}nRT

At the same temperature T, KE∝nKE \propto n (number of moles) — it does not depend on the identity/mass of the gas.

Step 1 — Moles of each gas:

  • Hydrogen: nH2=3 g2 g mol−1=1.5 moln_{H_2} = \dfrac{3\ g}{2\ g\,mol^{-1}} = 1.5\ mol …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.