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Q.Give hybridisation of carbon in

(a) CO3^2-
(b) diamond
(c) graphite
(d) fullerene
Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2018Subjective· 4mImportance★★★★★
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Carbon's hybridisation is determined by the number of sigma-bonded/lone-pair centres around it: 4 gives sp3sp^3 (tetrahedral), 3 gives sp2sp^2 (planar/trigonal).

(a) CO32−\text{CO}_3^{2-} (carbonate ion): the central carbon is bonded to 3 oxygen atoms with no lone pair on carbon, and the ion is trigonal planar with delocalized π\pi bonding (resonance) across all 3 C-O bonds. Carbon is sp2sp^2 hybridized (three sp2sp^2 orbitals form 3 σ\sigma bonds to O; the unhybridized 2p2p orbital takes part in delocalized π\pi bonding).

(b) Diamond: each carbon atom is bonded to 4 other carbon atoms by single covalent bonds in a rigid three-dimensional tetrahedral network. Carbon is sp3sp^3 hybridized, which explains diamond's tetrahedral bond angles (109.5°109.5°) and extreme hardness.

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