Skip to content
Question of 145

Q.Transform the following straight line equation into normal form 3x+4y=53x + 4y = 5.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2023Subjective· 2mImportance★★★★★
0% · 0/145 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Divide 3x+4y=53x+4y=5 by 32+42=5\sqrt{3^2+4^2}=5 to get 35x+45y=1\frac{3}{5}x+\frac{4}{5}y=1.

The normal form of a line is xcos⁡α+ysin⁡α=px\cos\alpha+y\sin\alpha=p, where p≥0p\ge0 is the perpendicular distance from the origin and α\alpha its inclination. To convert 3x+4y=53x+4y=5, divide throughout by 32+42=5\sqrt{3^2+4^2}=5 (the right side is already positive): …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.