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Q.Find the equation of the straight line parallel to the line 3x+4y=73x + 4y = 7 and passing through the point of intersection of the lines x−2y−3=0x - 2y - 3 = 0 and x+3y−6=0x + 3y - 6 = 0.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2024Subjective· 7mImportance★★★★★
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Find the point of intersection of the two given lines, then use the family-of-lines idea: any line parallel to 3x+4y=73x+4y=7 has the form 3x+4y=k3x+4y=k; fix kk using the point.

Intersection of x−2y−3=0x-2y-3=0 and x+3y−6=0x+3y-6=0: subtract the first from the second:

(x+3y)−(x−2y)=6−3  ⟹  5y=3  ⟹  y=35(x+3y)-(x-2y)=6-3 \implies 5y=3 \implies y=\frac35

x=3+2y=3+65=215x = 3+2y = 3+\frac65 = \frac{21}{5}

Intersection point: (215, 35)\left(\dfrac{21}{5},\ \dfrac35\right).

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