Q.Explain Celsius and Fahrenheit scales of temperature. Obtain the relation between Celsius and Fahrenheit scales of temperature.

Showing the 12 most recent of 23 on this concept.

1. CBSE 2026Set ANNUAL1 mark
   Q.Fill in the blank: The boiling point of water is ______ Celsius at 1.013 bar pressure.

   ›Reveal solutionSolution

   Water's normal boiling point, at standard atmospheric pressure of 1.013 bar, is 100°C (373.15 K).

   The boiling point of a liquid is the temperature at which its vapour pressure equals the external (atmospheric) pressure. This value depends on the surrounding pressure — at lower pressures (e.g., high altitude) water boils at a lower temperature, and at higher pressures it boils at a higher temperature. The standard atmospheric pressure …

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2. CBSE 2026Set ANNUAL1 markMCQ
   Q.The temperature at which Celsius temperature and Fahrenheit temperature are equal, is

   (a) 0°

   (b) 40°

   (c) − 40°

   (d) − 32°

   ›Reveal solutionSolution

   Celsius and Fahrenheit are equal at -40 degrees. Answer (C).

   The conversion is F = (9/5)C + 32. Set F = C = x:

   x = (9/5)x + 32

   x - (9/5)x = 32

   -(4/5)x = 32

   x = -40.

   …

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3. CBSE 2025Set ANNUAL1 markMCQ
   Q.The temperature which have same numerical value in Celsius and Fahrenheit scales is (A) 40° (B) -40°C (C) 100° (D) 273°

   ›Reveal solutionSolution

   The Celsius and Fahrenheit scales read the same numerical value at -40°.

   The relation between Celsius (C) and Fahrenheit (F) scales is:

   $\dfrac{C}{5} = \dfrac{F-32}{9}$

   Setting $C = F$ (equal numerical value) and solving:

   …

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4. CBSE 2025Set hz1 markMCQ
   Q.On the basis of absolute zero as the scale of temperature, the ice melts at:

   (a) 100 degrees

   (b) 273.15 K

   (c) 373.15 K

   (d) None of them

   ›Reveal solutionSolution

   The Kelvin scale is defined so that its zero coincides with absolute zero, and the ice point (0 degree C, where ice melts under standard pressure) is 273.15 K on this scale.

   The absolute (Kelvin) temperature scale is related to the Celsius scale by:

   T(K) = T(degree C) + 273.15

   The melting point of ice (the ice point) under standard atmospheric pressure is 0 degree C by definition of the Celsius scale. Converting this to the Kelvin scale:

   T(K) = 0 + 273.15 = 273.15 K

   …

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5. CBSE 2024Set ANNUAL1 markMCQ
   Q.The temperature of a body is found in Kelvin scale as x K and in Fahrenheit scale x°F. The value of x will be (A) 574.25 (B) 301.25 (C) 335 (D) 365

   ›Reveal solutionSolution

   The temperature at which the Kelvin and Fahrenheit numerical values coincide is $x=574.25$.

   Conversion: $°F=\dfrac95(K-273)+32$. Setting both readings equal to $x$: $x=\dfrac95(x-273)+32$.

   …

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6. CBSE 2024Set SET-AP55001 markMCQ
   Q.The relation between the Centigrade (Celsius) temperature scale and the Kelvin temperature scale is:

   (a) c = k - 273

   (b) c = k + 273

   (c) c = k + 100

   (d) c = k - 100

   ›Reveal solutionSolution

   The Celsius and Kelvin scales have the same size of degree but different zero points: 0°C = 273 K (more precisely 273.15 K), so C = K − 273.

   The Kelvin scale starts at absolute zero (0 K), while the Celsius scale sets 0°C at the freezing point of water. The freezing point of water is 273.15 K, so to convert from Kelvin to Celsius you subtract 273 (approximately): …

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7. CBSE 2024Set SET-AP55001 mark
   Q.At what temperature will the readings of the Fahrenheit and Celsius scales be equal?

   ›Reveal solutionSolution

   The Fahrenheit and Celsius scales give the same numerical reading at exactly −40 degrees.

   The conversion between the two scales is:

   F = (9/5)C + 32

   Setting F = C (both readings equal, call the common value x):

   x = (9/5)x + 32

   x − (9/5)x = 32

   −(4/5)x = 32

   x = 32 × (−5/4) = −40

   …

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8. CBSE 2024Set ANNUAL1 markMCQ
   Q.The SI unit of temperature is

   (a) A) °C

   (b) B) °F

   (c) C) K

   (d) D) Kg

   ›Reveal solutionSolution

   [!TLDR]

   C) K

   Why

   Kelvin is the SI base unit of thermodynamic …

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9. CBSE 2023Set ANNUAL1 markMCQ
   Q.SI unit of temperature is

   (a) Kelvin

   (b) Celsius

   (c) Fahrenheit

   (d) Centigrade

   ›Reveal solutionSolution

   Kelvin is the SI base unit for temperature; Celsius, Fahrenheit and Centigrade are common but non-SI temperature scales.

   The International System of Units (SI) defines seven base units, one for each fundamental physical quantity. For temperature, the SI base unit is the kelvin (K), defined via the thermodynamic (absolute) temperature scale, with 0 K = absolute zero. Celsius (°C) is an SI-accepted derived scale (T(K) = …

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10. CBSE 2023Set ANNUAL1 markMCQ
    Q.Temperature difference of 20°C is equivalent to:

    (a) 20 K

    (b) 293 K

    (c) 253 K

    (d) 0 K

    ›Reveal solutionSolution

    Celsius and Kelvin scales have identically sized degrees, so a temperature DIFFERENCE of 20 degC is exactly 20 K -- only absolute temperature readings differ by the 273 offset, not temperature intervals.

    The relation between an absolute Celsius reading and Kelvin reading is T(K) = T(degC) + 273. For two temperatures T1 and T2 in Celsius, converting both to Kelvin:

    T1(K) = T1(degC) + 273

    T2(K) = T2(degC) + 273

    Subtracting: T2(K) - T1(K) = T2(degC) - T1(degC)

    …

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11. CBSE 2023Set ANNUAL1 markMCQ
    Q.Absolute zero of temperature is:

    (a) 100°C

    (b) 273°C

    (c) −273°C

    (d) −273.15°C

    ›Reveal solutionSolution

    Absolute zero = −273.15 °C = 0 K.

    The Kelvin (absolute) scale is related to Celsius by T(K) = t(°C) + 273.15. At absolute zero T = 0 K, so t = −273.15 °C. This is the lowest temperature theore …

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12. CBSE 2023Set ANNUAL1 markMCQ
    Q.Temprature which has equal reading on Celcius and Faherenhit scale:

    (a) 0°

    (b) 30°

    (c) −40°

    (d) 40°

    ›Reveal solutionSolution

    The two scales agree at −40°.

    The Celsius–Fahrenheit relation is F = (9/5)C + 32. For equal readings put F = C = x:

    …

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