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Physics · Ch 13 — Atoms

Summary

Summary

  • Rutherford’s α\alpha-particle scattering experiment showed that the atom has a tiny, dense, positively charged nucleus, with electrons orbiting at large distances — most of the atom is empty space.
  • The nuclear model could not explain the stability of atoms or the discrete line spectra observed; classical physics predicted that accelerating electrons would spiral into the nucleus, emitting a continuous spectrum.
  • Bohr’s postulates for the hydrogen atom:
    • Electrons move only in certain stationary orbits where angular momentum is quantized: mvr=nh2πm v r = n \frac{h}{2\pi}, n=1,2,3,…n = 1,2,3,\dots
    • While in these orbits, electrons do not radiate energy.
    • Radiation is emitted or absorbed only when an electron jumps between orbits: hν=Ei−Efh\nu = E_i - E_f.
  • From Bohr’s model, the radius of the nnth orbit in hydrogen is rn=n2a0r_n = n^2 a_0, where a0=0.529 A˚a_0 = 0.529 \,\text{Å} is the Bohr radius.
  • The energy of the nnth level is En=−13.6n2 eVE_n = -\frac{13.6}{n^2} \,\text{eV} (ground state n=1n=1: −13.6-13.6 eV). Energy is negative because the electron is bound.
  • The wavelength of emitted/absorbed light is given by the Rydberg formula: 1λ=R(1nf2−1ni2)\frac{1}{\lambda} = R \left( \frac{1}{n_f^2} - \frac{1}{n_i^2} \right), with R=1.097×107 m−1R = 1.097 \times 10^7 \,\text{m}^{-1}.
  • Spectral series of hydrogen:
    • Lyman (ultraviolet): nf=1n_f = 1, ni=2,3,…n_i = 2,3,\dots
    • Balmer (visible): nf=2n_f = 2, ni=3,4,…n_i = 3,4,\dots
    • Paschen (infrared): nf=3n_f = 3, ni=4,5,…n_i = 4,5,\dots
    • Brackett and Pfund (far infrared): nf=4n_f = 4 and 55 respectively. …