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Physics · Ch 2 — Ray Optics and Optical Instruments

The Mirror Equation

2.2.3

The Mirror Equation

The Mirror Equation: Connecting Object Distance, Image Distance, and Focal Length

The mirror equation is the fundamental relationship that links three key distances for any spherical mirror (concave or convex):

  • Object distance (uu) – distance of the object from the pole of the mirror.
  • Image distance (vv) – distance of the image from the pole.
  • Focal length (ff) – distance of the focus from the pole.

It is derived using geometry and the laws of reflection, assuming paraxial rays (rays that make small angles with the principal axis).

Derivation in Steps
  1. Set up the geometry

    Consider a concave mirror forming a real, inverted image of an object. Two similar right-angled triangles are identified:

    • △A′B′F\triangle A'B'F and △MPF\triangle MPF (for paraxial rays, MPMP is nearly perpendicular to CPCP).
    • △A′B′P\triangle A'B'P and △ABP\triangle ABP (because ∠APB=∠A′PB′\angle APB = \angle A'PB').
  2. Relate distances using similarity

    From the first pair:

B′A′PM=B′FFP\frac{B'A'}{PM} = \frac{B'F}{FP}

Since PM=ABPM = AB, this becomes:

B′A′AB=B′FFP(Equation 9.4)\frac{B'A'}{AB} = \frac{B'F}{FP} \quad \text{(Equation 9.4)}

From the second pair:

B′A′AB=B′PBP(Equation 9.5)\frac{B'A'}{AB} = \frac{B'P}{BP} \quad \text{(Equation 9.5)}

  1. Combine the ratios Equating the right-hand sides of (9.4) and (9.5):

B′FFP=B′PBP\frac{B'F}{FP} = \frac{B'P}{BP}

Using B′F=B′P−FPB'F = B'P - FP, we get:

B′P−FPFP=B′PBP(Equation 9.6)\frac{B'P - FP}{FP} = \frac{B'P}{BP} \quad \text{(Equation 9.6)}

  1. Apply the Cartesian sign convention

    Light travels from object to mirror — this direction is taken as positive.

    To reach the object (ABAB), image (A′B′A'B'), and focus (FF) from the pole (PP), we travel opposite to the incident light. Hence:

    • B′P=−vB'P = -v
    • FP=−fFP = -f
    • BP=−uBP = -u

    Substituting into (9.6):

−v−(−f)−f=−v−u\frac{-v - (-f)}{-f} = \frac{-v}{-u}

Simplifying:

−v+f−f=vu\frac{-v + f}{-f} = \frac{v}{u}

v−ff=vu\frac{v - f}{f} = \frac{v}{u}

Cross-multiplying:

u(v−f)=vfu(v - f) = vf

uv−uf=vfuv - uf = vf

uv=vf+ufuv = vf + uf

Divide both sides by uvfuvf:

1f=1u+1v\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

  1. The mirror equation Rearranging gives the standard form:

1u+1v=1f\frac{1}{u} + \frac{1}{v} = \frac{1}{f}

This is valid for all spherical mirrors (concave or convex) and for both real and virtual images, provided the sign convention is followed.

Linear Magnification (mm)

Magnification tells us how the image size compares to the object size.

  • Definition:

m=h′hm = \frac{h'}{h}

where h′h' = image height, hh = object height (both with sign).

  • Relation to distances: From similar triangles △A′B′P\triangle A'B'P and △ABP\triangle ABP:

h′h=−vu\frac{h'}{h} = -\frac{v}{u}

Hence:

m=−vum = -\frac{v}{u} …

Figure 9.5Ray diagram for image formation by a concave mirror.
Fig. 9.5 — Ray diagram for image formation by a concave mirror.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 9.5: Ray Diagram for a Concave Mirror — Object Beyond C

The figure shows a concave mirror drawn as an arc opening to the left, with its reflecting surface on the right side of the diagram. A horizontal line through the centre of the mirror is the principal axis. On this axis, three key points are marked from left to right: the pole PP (at the mirror's vertex), the focus FF, and the centre of curvature CC. The distance PFPF is the focal length ff, and PC=2fPC = 2f is the radius of curvature RR.

An object is represented by an upright arrow ABAB, with its base BB on the principal axis and its tip AA above the axis. The object is placed beyond CC (to the left of CC). From point AA, three special rays are drawn:

  1. A ray parallel to the principal axis, which after reflection passes through FF.
  2. A ray passing through CC, which strikes the mirror normally and retraces its path back through CC.
  3. A ray passing through FF, which after reflection becomes parallel to the principal axis.

These three reflected rays converge at a single point A′A' on the left side of the mirror, between FF and CC. From A′A', a perpendicular is dropped to the principal axis, meeting it at B′B'. The image A′B′A'B' is a downward-pointing arrow — real, inverted, and diminished (smaller than the object).

Physical Idea Taught

The diagram illustrates the mirror equation and magnification formula for a concave mirror when the object is beyond CC. It shows that:

  • The image is real (rays actually meet), inverted, and smaller than the object.
  • The image lies between FF and CC.
  • The geometry of similar triangles ( △A′B′F∼△MPF\triangle A'B'F \sim \triangle MPF and △A′B′P∼△ABP\triangle A'B'P \sim \triangle ABP ) leads directly to the mirror equation.

Key Formulas Derived from This Figure

Using the sign convention (incident light direction is positive, so distances to object, image, and focus are negative for a concave mirror), the textbook derives:

Mirror equation:

1v+1u=1f\frac{1}{v} + \frac{1}{u} = \frac{1}{f}

where:

  • uu = object distance from pole PP (negative, here u=−BPu = -BP) …
Figure 9.6Image formation by (a) a concave mirror with object between P and F, and (b) a convex mirror.
Fig. 9.6 — Image formation by (a) a concave mirror with object between P and F, and (b) a convex mirror.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

Figure 9.6 consists of two separate ray diagrams, labeled (a) and (b), each showing how a spherical mirror forms a virtual image.

Panel (a): Concave mirror with object between P and F

  • The mirror is concave, with its reflecting surface on the left. The principal axis is a horizontal line through the centre.
  • Labels: Pole P, focus F, centre of curvature C (all on the principal axis). The object AB is an upright arrow placed between P and F (i.e., object distance ∣u∣<∣f∣|u| < |f|).
  • Two rays are drawn from point A of the object:
    1. A ray parallel to the principal axis — after reflection, it passes through F.
    2. A ray directed toward C (or through F) — after reflection, it becomes parallel to the axis.
  • After reflection, these rays diverge (they move apart). Their backward extensions (shown as dashed lines) meet behind the mirror at point A′.
  • The image A′B′ is:
    • Virtual (rays do not actually meet; only their extensions do),
    • Erect (same orientation as object),
    • Magnified (larger than object).
  • The image lies behind the mirror, between P and F on the virtual side.

Panel (b): Convex mirror

  • The mirror is convex, with its reflecting surface on the left. The principal axis is again horizontal.
  • Labels: P, F, C (for a convex mirror, F and C lie behind the mirror). The object AB is an upright arrow placed in front of the mirror (any distance).
  • Two rays from point A:
    1. A ray parallel to the principal axis — after reflection, it appears to come from F behind the mirror.
    2. A ray directed toward C (behind the mirror) — after reflection, it retraces its path.
  • The reflected rays diverge; their dashed backward extensions meet behind the mirror at A′.
  • The image A′B′ is:
    • Virtual,
    • Erect,
    • Diminished (smaller than object),
    • Located between P and F behind the mirror.

Physical idea taught by the figure

The figure illustrates that virtual images are formed when reflected rays diverge — the brain “sees” the image where the rays appear to come from. For a concave mirror, this happens only when the object is closer than the focus (between P and F). For a convex mirror, it happens for any object position — the image is always virtual, erect, and diminished.


Key formula(s) developed with this figure

The mirror equation and magnification formula are derived using similar triangles from ray diagrams (like Fig. 9.5) and are valid for both real and virtual images (including those in Fig. 9.6):

1u+1v=1f\frac{1}{u} + \frac{1}{v} = \frac{1}{f}

  • uu = object distance (negative when object is in front of mirror, as per sign convention)
  • vv = image distance (negative for real images in front, positive for virtual images behind) …