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Q.Describe erythroblastosis foetalis.

Telangana TsbieTelangana Board of Intermediate Education 2026Subjective· 4mImportance★★★★★
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Erythroblastosis foetalis is destruction of a foetus's red blood cells by the mother's anti-Rh antibodies when an Rh-negative mother carries a second Rh-positive foetus; it is prevented by injecting anti-Rh (anti-D) antibodies after the first delivery.

Cause (Rh incompatibility):

  • A person is Rh-positive if the Rh antigen (Rh factor) is present on red blood cells, and Rh-negative if it is absent.
  • A problem arises when an Rh-negative mother carries an Rh-positive foetus (the baby inheriting Rh-positive from the father).

Mechanism:

  1. During the first pregnancy the mother's and foetus's blood normally stay separated by the placenta, so no harm occurs. However, during delivery, some Rh-positive foetal blood leaks into the Rh-negative mother's circulation.
  2. In response, the mother's immune system produces anti-Rh antibodies. So the first baby is usually safe.
  3. If she later conceives another Rh-positive foetus, her anti-Rh antibodies cross the placenta into the foetal blood.
  4. These antibodies agglutinate and destroy (haemolyse) the foetal red blood cells.

Effects on the baby:

  • Severe anaemia, jaundice (due to released bilirubin), oedema, and immature erythroblasts appearing in the blood (hence the name 'erythroblastosis foetalis'). It can be fatal or cause brain damage. …

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