Q.What is the correct order of decreasing stability of the following cations?
I. CH3—CH^+—CH3
II. CH3—CH^+—OCH3
III. CH3—CH^+—CH2—OCH3
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Carbocation stability depends on how well the positive centre is fed electrons. The
methoxy group () directly on the cationic carbon (II) donates its oxygen
lone pair by resonance — powerful stabilisation. One carbon further away (III) the
oxygen can no longer donate by resonance and its electronegative pull now
destabilises the cation, dropping it below the plain secondary ion (I).
Order: II > I > III.
Two effects compete for an oxygen-substituted carbocation: the oxygen lone pair
(stabilising, but only when it can overlap the empty p-orbital, i.e. when oxygen is
directly attached) and the oxygen's electronegativity (an electron-withdrawing
pull that always destabilises a cation).
-
Cation I: (isopropyl cation). A plain secondary carbocation,
stabilised only by the effect and hyperconjugation of two methyl groups. This is
our reference.
-
Cation II: . The methoxy oxygen is bonded directly to the
cationic carbon, so its lone pair overlaps the empty p-orbital and delocalises the
charge onto oxygen:
Every atom gains an octet; this resonance donation far outweighs oxygen's pull,
making II the most stable. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.