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Worked Examples · Example 12
Q.

Calculate mean, variance and standard deviation for the following distribution.

ClassesFrequency
30-403
40-507
50-6012
60-7015
70-808
80-903
90-1002
Tripura TbseTextbookSubjective· 5mImportance★★★★★est
38% · 34/90 Questions
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For this distribution the mean is xˉ=62\bar{x}=62, the variance is σ2=201\sigma^2=201, and the standard deviation is σ=201≈14.18\sigma=\sqrt{201}\approx 14.18.

For grouped data we assume each observation lies at its class midpoint. We find the mean, then the variance as the frequency-weighted average of squared deviations from the mean (population form, dividing by NN), and the standard deviation as its square root — the standard NCERT Class 11 Maths Statistics procedure.

Step 1 — Class marks and mean.

Classxix_ifif_ifixif_i x_i
30–40353105
40–50457315
50–605512660
60–706515975
70–80758600
80–90853255
90–100952190
Total503100

xˉ=310050=62.\bar{x}=\frac{3100}{50}=62.

Step 2 — Squared deviations weighted by frequency.

xix_ifif_ixi−62x_i-62(xi−62)2(x_i-62)^2fi(xi−62)2f_i(x_i-62)^2
353-277292187
457-172892023
5512-749588
651539135
758131691352

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