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Exercise 13.2 · Q6
Q.

Find the mean and standard deviation using short-cut method.

xix_ifif_i
602
611
6212
6329
6425
6512
6610
674
685
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Mean =64= 64 and standard deviation ≈1.69\approx 1.69.

Short-cut (step-deviation) method

Take assumed mean A=64A = 64 and h=1h = 1, so di=xi−64d_i = x_i - 64. Then xˉ=A+∑fidi∑fi\bar{x} = A + \dfrac{\sum f_i d_i}{\sum f_i} and σ=h∑fidi2∑fi−(∑fidi∑fi)2\sigma = h\sqrt{\dfrac{\sum f_i d_i^2}{\sum f_i} - \left(\dfrac{\sum f_i d_i}{\sum f_i}\right)^2}.

Step-by-step solution

xix_ifif_idi=xi−64d_i = x_i-64fidif_i d_ifidi2f_i d_i^2
602−4-4−8-832
611−3-3−3-39
6212−2-2−24-2448
6329−1-1−29-2929
6425000
651211212
661022040

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