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Exercise 13.2 · Q10
Q.

The diameters of circles (in mm) drawn in a design are given below:

DiametersNo. of circles
33-3615
37-4017
41-4421
45-4822
49-5225

Calculate the standard deviation and mean diameter of the circles.

[Hint First make the data continuous by making the classes as 32.5-36.5, 36.5-40.5, 40.5-44.5, 44.5-48.5, 48.5-52.5 and then proceed.]

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After making the classes continuous, the mean diameter is 43.5 mm and the standard deviation is about 5.55 mm.

The classes have gaps (33–36, 37–40, …), so we first make them continuous by subtracting 0.5 from each lower limit and adding 0.5 to each upper limit, as the hint suggests. Then we work with the class marks.

Step 1 — Continuous classes and class marks (xix_i).

The classes become 32.5–36.5, 36.5–40.5, 40.5–44.5, 44.5–48.5, 48.5–52.5, with class marks 34.5, 38.5, 42.5, 46.5, 50.5.

Classfif_ixix_ifixif_i x_ifixi2f_i x_i^2
32.5–36.51534.5517.517853.75
36.5–40.51738.5654.525198.25
40.5–44.52142.5892.537931.25
44.5–48.52246.51023.047569.50
48.5–52.52550.51262.563756.25
Total1004350192309

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