Skip to content
Exercise 9.1 · Q3

Q.Find the distance between P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2) when:

(i) PQPQ is parallel to the y-axis,
(ii) PQPQ is parallel to the x-axis.
Tripura TbseTextbookSubjective· 2mImportance★★★★★est
2% · 3/145 Questions
✓ Free question

When PQPQ is parallel to the yy-axis, x1=x2x_1 = x_2 and the distance is ∣y2−y1∣|y_2 - y_1|; when PQPQ is parallel to the xx-axis, y1=y2y_1 = y_2 and the distance is ∣x2−x1∣|x_2 - x_1|.

Why an axis-parallel segment simplifies the distance formula

The distance between any two points P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2) is given by

d=(x2−x1)2+(y2−y1)2.d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

This formula measures movement in both the horizontal and vertical directions at once. When the segment PQPQ is parallel to one of the axes, movement happens along only one direction, so one of the two terms under the square root becomes zero.

(i) PQPQ parallel to the yy-axis

A line parallel to the yy-axis is vertical, so every point on it has the same xx-coordinate:

x1=x2.x_1 = x_2.

Substituting x2−x1=0x_2 - x_1 = 0 into the distance formula:

d=0+(y2−y1)2=(y2−y1)2=∣y2−y1∣.d = \sqrt{0 + (y_2 - y_1)^2} = \sqrt{(y_2-y_1)^2} = |y_2 - y_1|.

(ii) PQPQ parallel to the xx-axis

A line parallel to the xx-axis is horizontal, so every point on it has the same yy-coordinate:

y1=y2.y_1 = y_2.

Substituting y2−y1=0y_2 - y_1 = 0 into the distance formula:

d=(x2−x1)2+0=(x2−x1)2=∣x2−x1∣.d = \sqrt{(x_2-x_1)^2 + 0} = \sqrt{(x_2-x_1)^2} = |x_2 - x_1|.

✓Final answer

When PQPQ is parallel to the yy-axis, PQ=∣y2−y1∣PQ = |y_2 - y_1|. When PQPQ is parallel to the xx-axis, PQ=∣x2−x1∣PQ = |x_2 - x_1|.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.