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Q.(a) At 27°C, what quantity of CaCl2 (i = 2.47) must be dissolved in 2.5 litres of water so that the osmotic pressure of the solution is 0.75 atm? (Ca = 40)

(b) State Henry's law and mention the significance of Henry's constant.
Tripura TbseHigher Secondary (+2 Stage) Examination 2024Subjective· 4mImportance★★★★★
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Using π = iCRT for the osmotic pressure of an electrolyte solution and solving for moles, then mass, of CaCl2 gives about 3.42 g; Henry's law separately relates a gas's equilibrium partial pressure above a solution to its mole fraction dissolved in it.

  1. Osmotic pressure with van't Hoff factor: π = i × (n/V) × R × T Given: π = 0.75 atm, i = 2.47, V = 2.5 L, R = 0.0821 L atm K⁻¹ mol⁻¹, T = 27°C = 300 K Solving for n (moles of CaCl2): n = πV / (iRT) = (0.75 × 2.5) / (2.47 × 0.0821 × 300) = 1.875 / 60.84 = 0.0308 mol Molar mass of CaCl2 = 40 + 2(35.5) = 111 g/mol Mass = n × M = 0.0308 × 111 ≈ 3.42 g
  2. Henry's law: at a given temperature, the partial pressure (p) of a gas over a solution is directly proportional to the mole fraction (x) of that gas dissolved in the solution: p = KH × x where KH is Henry's law constant (different for every gas–solvent pair, and dependent on temperature). …

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