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Q.Using Kirchhoff's laws, determine the values of I and R in the given circuit. (Assume that no current flows through the 4Ω resistor.)

A Kirchhoff network with nodes F, E, D, A, B, C containing 1 ohm, 4 ohm and R resistors and 9 V, 6 V and 3 V cells — Class 12 Physics find-I-and-R question
Figure
Tripura TbseHigher Secondary (+2 Stage) Examination 2025Subjective· 2mImportance★★★★★
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Since the 4(ohm) branch carries no current, the whole outer loop F-E(D)-C-B-A-F behaves as a single-current series loop; combine its KVL equation with the zero-current branch's potential-balance condition (V_E - V_B = 6V, the full 6V-cell EMF with no IR drop across the 4-ohm resistor) to solve simultaneously for I and R.

Since E and D are joined by a plain connecting wire, they are at the same potential (VE=VDV_E=V_D). Because no current flows through the 4(ohm)/6V branch connecting E to B, that branch draws no current from the rest of the circuit -- the main current I simply circulates around the single outer loop F to E(D) to C to B to A and back to F.

Step 1 -- the zero-current branch. With no current through the 4(ohm) resistor, there is no IR drop across it, so the potential difference between E and B is due entirely to the 6V cell in that branch:

VE−VB=6 V...(1)V_E-V_B=6\text{ V}\quad\text{...(1)}

Step 2 -- the same potential difference via the main loop. Going from E through R (between D/E and C) and then through the 3V cell to reach B (reading the cells' polarities as oriented in the printed figure): …

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