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NCERT Exemplar · Q31

Q.A circular coil expands radially in a region of magnetic field and no electromotive force is produced in the coil. This can be because

(a) the magnetic field is constant.
(b) the magnetic field is in the same plane as the circular coil and it may or may not vary.
(c) the magnetic field has a perpendicular (to the plane of the coil) component whose magnitude is decreasing suitably.
(d) there is a constant magnetic field in the perpendicular (to the plane of the coil) direction.
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A radially expanding coil has increasing area AA. No emf appears only if the linked flux Φ=B⊥A\Phi = B_\perp A stays constant — either because B⊥=0B_\perp = 0 (field in the plane), or because B⊥B_\perp decreases as AA grows so their product is fixed. Correct options: (b) and (c).

Concept understanding. Faraday's law gives E=−dΦ/dt\mathcal{E} = -d\Phi/dt, with Φ=∫B⃗⋅dA⃗=B⊥A\Phi = \int\vec{B}\cdot d\vec{A} = B_\perp A, where B⊥B_\perp is the component of B⃗\vec{B} perpendicular to the plane of the coil. As the coil expands radially, AA increases; for zero emf the flux must not change with time.

Testing each option.

  • (a) Field simply "constant": if it is constant and has a perpendicular component, then Φ=B⊥A\Phi = B_\perp A grows as AA increases ⇒\Rightarrow emf is produced. Wrong.
  • (b) Field lies in the same plane as the coil: its perpendicular component is zero, so Φ=0\Phi = 0 at all times regardless of whether the field varies. dΦ/dt=0⇒d\Phi/dt = 0 \Rightarrow no emf. Correct. …

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