Q.The locus of a point for which is
(A) equation of -axis
(B) equation of -axis
(C) equation at -axis
(D) none of these
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Start your 14-day free trial to unlock the full solution →A point with and lies on the -axis; these two equations together define the -axis in three-dimensional space.
Understanding Coordinate Axes as Loci
In three-dimensional Cartesian geometry, a single equation represents a surface (like is the -plane), but to pin down a line we need two independent equations. Think of it as progressively constraining freedom: three coordinates give us all of space, fixing one leaves a plane, fixing two leaves a line.
The coordinate axes themselves are special lines. Each axis is characterized by the other two coordinates being zero:
| Axis | Conditions | Points look like |
|---|---|---|
| -axis | ||
| -axis | ||
| -axis |
Working Through the Given Conditions
The problem asks for the locus of points satisfying and simultaneously.
-
Apply the first condition : This eliminates all points except those in the -plane. We're left with points of the form where and can be anything.
-
Apply the second condition : Now we further restrict to points where the -coordinate is also zero. Combined with , we have points of the form . …
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