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Worked Examples · Example 6

Q.If A×B={(p,q),(p,r),(m,q),(m,r)}A \times B = \{(p, q), (p, r), (m, q), (m, r)\}, find AA and BB.

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The Cartesian product A×BA \times B lists every ordered pair where the first element comes from AA and the second from BB. By collecting all distinct first coordinates we get AA, and all distinct second coordinates we get BB. Here, A={p,m}A = \{p, m\} and B={q,r}B = \{q, r\}.

The Cartesian product A×BA \times B is defined as the set of all ordered pairs (a,b)(a, b) where a∈Aa \in A and b∈Bb \in B. So if we are given the product, we can reverse the process: the first elements of the pairs come from AA, and the second elements come from BB.

Let’s look at the given set:

A×B={(p,q),(p,r),(m,q),(m,r)}.A \times B = \{(p, q), (p, r), (m, q), (m, r)\}.

  1. Identify the set AA. The first coordinate in each ordered pair is either pp or mm. No other first coordinates appear. So AA must contain exactly these two elements:

A={p,m}.A = \{p, m\}.

  1. Identify the set BB. The second coordinate in each ordered pair is either qq or rr. No other second coordinates appear. So BB must contain exactly these two elements:

B={q,r}.B = \{q, r\}.

  1. Verify completeness. If A={p,m}A = \{p, m\} and B={q,r}B = \{q, r\}, then A×BA \times B should have 2×2=42 \times 2 = 4 ordered pairs: (p,q),(p,r),(m,q),(m,r).(p, q), (p, r), (m, q), (m, r). …

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