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Exercise 2.1 · Q6

Q.If A×B={(a,x),(a,y),(b,x),(b,y)}A \times B = \{(a, x), (a, y), (b, x), (b, y)\}. Find AA and BB.

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The Cartesian product A×BA \times B lists all ordered pairs where the first element comes from AA and the second from BB. Reading off the components: A={a,b}A = \{a, b\} and B={x,y}B = \{x, y\}.

Understanding the Cartesian Product

The Cartesian product A×BA \times B is the set of all ordered pairs (p,q)(p, q) where p∈Ap \in A and q∈Bq \in B. Think of it as a systematic pairing: every element of AA gets matched with every element of BB.

If AA has mm elements and BB has nn elements, then A×BA \times B contains exactly m×nm \times n ordered pairs. The structure of these pairs reveals the original sets.

Extracting AA and BB from the product

We're given:

A×B={(a,x),(a,y),(b,x),(b,y)}A \times B = \{(a, x), (a, y), (b, x), (b, y)\}

The key insight is that the first coordinates of all pairs come from AA, and the second coordinates come from BB.

  1. Identify the first coordinates. Looking at each ordered pair, the first components are: a,a,b,ba, a, b, b. Removing duplicates (since sets contain unique elements), we get:

A={a,b}A = \{a, b\}

  1. Identify the second coordinates. The second components of the pairs are: x,y,x,yx, y, x, y. Again removing duplicates:

B={x,y}B = \{x, y\}

  1. Verify the result. If A={a,b}A = \{a, b\} and B={x,y}B = \{x, y\}, then forming all possible pairs: …

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