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NCERT Exemplar · Q15

Q.Find the values of xx for which the functions f(x)=3x2−1f(x) = 3x^2 - 1 and g(x)=3+xg(x) = 3 + x are equal

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To find when two functions are equal, we set their algebraic expressions equal to each other. This problem leads to a quadratic equation, 3x2−x−4=03x^2 - x - 4 = 0, which can be solved by factorization or the quadratic formula to find the values of xx. The values are x=43x = \frac{4}{3} and x=−1x = -1.

When we are asked to find the values of xx for which two functions, say f(x)f(x) and g(x)g(x), are equal, we are essentially looking for the input values of xx where both functions produce the exact same output value. Graphically, this corresponds to finding the xx-coordinates of the points where the graphs of y=f(x)y = f(x) and y=g(x)y = g(x) intersect.

To solve this algebraically, we simply set the expressions for f(x)f(x) and g(x)g(x) equal to each other and then solve the resulting equation for xx.

  1. Set the function expressions equal.

    The problem states that f(x)f(x) and g(x)g(x) are equal. So, we write:

    f(x)=g(x)f(x) = g(x)

  2. Substitute the given function definitions.

    We are given f(x)=3x2−1f(x) = 3x^2 - 1 and g(x)=3+xg(x) = 3 + x. Substituting these into the equation from Step 1:

    3x2−1=3+x3x^2 - 1 = 3 + x

  3. Rearrange the equation into a standard quadratic form.

    To solve this equation, we need to bring all terms to one side, setting the equation to zero. This will result in a standard quadratic equation of the form ax2+bx+c=0ax^2 + bx + c = 0.

    First, subtract xx from both sides:

    3x2−x−1=33x^2 - x - 1 = 3

    Next, subtract 33 from both sides:

    3x2−x−1−3=03x^2 - x - 1 - 3 = 0

    This simplifies to:

    3x2−x−4=03x^2 - x - 4 = 0

    A quadratic equation is an equation of the form ax2+bx+c=0ax^2 + bx + c = 0, where a,b,ca, b, c are constants and a≠0a \neq 0.

  4. Solve the quadratic equation.

    We now have the quadratic equation 3x2−x−4=03x^2 - x - 4 = 0. We can solve this using either factorization or the quadratic formula.

    Method 1: Factorization

    We look for two numbers that multiply to a⋅c=3⋅(−4)=−12a \cdot c = 3 \cdot (-4) = -12 and add up to b=−1b = -1. These numbers are −4-4 and 33.

    We can rewrite the middle term, −x-x, as −4x+3x-4x + 3x:

    3x2−4x+3x−4=03x^2 - 4x + 3x - 4 = 0

    Now, factor by grouping:

    x(3x−4)+1(3x−4)=0x(3x - 4) + 1(3x - 4) = 0

    (3x−4)(x+1)=0(3x - 4)(x + 1) = 0

    For the product of two factors to be zero, at least one of the factors must be zero: …

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