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Q.What is the solenoid? Obtain the expression for magnetic field inside a long current carrying solenoid. OR The work function of photoelectric surface is 4.0 eV. Radiation of frequency 3×10153 \times 10^{15} Hz is incident on it. Calculate the maximum velocity of emitted photo-electron.

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2025Subjective· 5mImportance★★★★★
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Applying Ampere's circuital law to a rectangular loop straddling the wall of a long solenoid gives a uniform axial interior field B=μ0nIB=\mu_0 n I. (An OR alternative on photoelectric emission is offered; the solenoid derivation is given here.)

What is a solenoid? A solenoid is a long cylindrical coil of many closely wound turns of insulated wire. When current flows, each turn acts like a small current loop; for a long solenoid the field is uniform and strong inside (directed along the axis) and almost zero outside.

Field inside — Ampere's law. Consider a rectangular Amperian loop abcdabcd of length LL along the axis, with side abab inside the solenoid (parallel to the axis) and side cdcd outside.

  • Along abab (inside): B⃗\vec B is uniform and parallel to the path → contribution =BL=BL.
  • Along bcbc and dada (perpendicular to B⃗\vec B): contribution =0=0.
  • Along cdcd (outside): B≈0B\approx 0 → contribution =0=0.

So ∮B⃗⋅dl⃗=BL\displaystyle\oint \vec B\cdot d\vec l = BL.

If nn is the number of turns per unit length, the length LL encloses nLnL turns, each carrying current II, so total enclosed current =nLI=nLI. Ampere's law: …

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