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NCERT Exemplar · Q47

Q.Arrange the following bonds in order of increasing ionic character giving reason.
N—H, F—H, C—H and O—H

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Ionic character in a bond depends on the electronegativity difference between the two atoms. The order of increasing ionic character is: C—H < N—H < O—H < F—H.

The idea is simple: a bond is more ionic when the two atoms have a larger difference in electronegativity. The more one atom pulls electrons toward itself, the more the bond behaves like it has separated charges — that’s ionic character. Covalent character, on the other hand, means the electrons are shared more equally.

So to rank these bonds, we just need the electronegativity values of the atoms involved. Here’s a quick reference (Pauling scale):

AtomElectronegativity
C2.5
N3.0
O3.5
F4.0
H2.1

Now let’s work through each bond.

  1. C—H: Electronegativity difference = ∣2.5−2.1∣=0.4|2.5 - 2.1| = 0.4. This is the smallest difference here, so C—H is the most covalent (least ionic).

  2. N—H: Difference = ∣3.0−2.1∣=0.9|3.0 - 2.1| = 0.9. Larger than C—H, so more ionic character.

  3. O—H: Difference = ∣3.5−2.1∣=1.4|3.5 - 2.1| = 1.4. Bigger still. …

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