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Worked Examples · Example 7

Q.The marks obtained by a student of Class XI in first and second terminal examination are 62 and 48, respectively. Find the minimum marks he should get in the annual examination to have an average of at least 60 marks.

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We need the minimum annual exam score so that the average of three exams (62, 48, and the unknown) is at least 60. Using the weighted average concept, the required minimum is 70 marks.

The core idea here is a weighted average — but with equal weights. When we say "average of at least 60 marks" over three exams, we mean the sum of all three marks divided by 3 must be ≥ 60. This is the same as saying the total sum must be at least 180.

Why think of it as a weighted average? Because each exam contributes equally to the final average. If the annual exam had a higher weight (like in some grading systems), the calculation would change. Here, all three are equally important.

Let’s work through it step by step.

  1. Set up the inequality. Let the annual exam marks be xx. The average of the three exams is:

62+48+x3\frac{62 + 48 + x}{3}

We need this to be at least 60:

62+48+x3≥60\frac{62 + 48 + x}{3} \geq 60

  1. Clear the denominator. Multiply both sides by 3 (a positive number, so the inequality direction stays the same):

62+48+x≥18062 + 48 + x \geq 180

  1. Simplify the left side. Add the known marks:

110+x≥180110 + x \geq 180

  1. Isolate xx. Subtract 110 from both sides: x≥70x \geq 70 …

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