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Exercise 5.1 · Q9

Q.x+x2+x3<11x + \dfrac{x}{2} + \dfrac{x}{3} < 11

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The key idea is to combine the fractional terms by finding a common denominator, then solve the resulting linear inequality. The solution is x<6x < 6.

Why This Approach Works

When you see an inequality with fractions like x2\frac{x}{2} and x3\frac{x}{3}, the natural instinct is to panic. Don't. The core principle is the same as solving any linear inequality: isolate xx. The fractions are just numbers — they add, subtract, and multiply like any other number. The only extra care needed is when multiplying or dividing by a negative number (which flips the inequality sign), but here all coefficients are positive, so we're safe.

The trick is to rewrite every term with a common denominator so the inequality becomes a single fraction. Then multiply through to clear the denominator, and you're left with a simple linear inequality.

Step-by-Step Solution

  1. Write all terms with a common denominator. The denominators are 11 (for xx), 22, and 33. The least common multiple of 1,2,31, 2, 3 is 66. So rewrite each term as a fraction with denominator 66:

x=6x6,x2=3x6,x3=2x6.x = \frac{6x}{6}, \quad \frac{x}{2} = \frac{3x}{6}, \quad \frac{x}{3} = \frac{2x}{6}.

  1. Combine the fractions. Add the numerators over the common denominator:

6x6+3x6+2x6=6x+3x+2x6=11x6.\frac{6x}{6} + \frac{3x}{6} + \frac{2x}{6} = \frac{6x + 3x + 2x}{6} = \frac{11x}{6}.

So the inequality becomes:

11x6<11.\frac{11x}{6} < 11.

  1. Clear the denominator by multiplying both sides by 6. Since 6>06 > 0, the inequality sign stays the same:

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