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Exercises · Q9

Q.Find the compound interest on ₹10,000 for 1 year at 8% per annum, compounded quarterly.

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Here P=₹10,000P = ₹10{,}000, r=8%r = 8\% per annum, t=1t = 1 year, compounded quarterly.

Step 1 — Convert to quarterly terms. Periods =4t=4= 4t = 4. Rate per quarter =r4=84=2%= \dfrac{r}{4} = \dfrac{8}{4} = 2\%.

Step 2 — Apply the quarterly formula.

A=10,000(1+8400)4=10,000(1.02)4A = 10{,}000\left(1+\frac{8}{400}\right)^{4} = 10{,}000(1.02)^{4}

Step 3 — Evaluate period by period. 10,000→10,200→10,404→10,612.08→10,824.321610{,}000 \to 10{,}200 \to 10{,}404 \to 10{,}612.08 \to 10{,}824.3216. …

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