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Exercises · Q11

Q.Find the compound interest on ₹10,000 for 3 years at 10% per annum, compounded half-yearly.

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Here P=₹10,000P = ₹10{,}000, r=10%r = 10\% per annum, t=3t = 3 years — the maximum time span this chapter's syllabus allows — compounded half-yearly, giving 2t=62t = 6 half-year periods at 5%5\% per period.

Step 1 — Apply the half-yearly formula.

A=10,000(1+10200)6=10,000(1.05)6A = 10{,}000\left(1+\frac{10}{200}\right)^{6} = 10{,}000(1.05)^{6}

Step 2 — Evaluate period by period. 10,000→10,500→11,025→11,576.25→12,155.0625→12,762.815625→13,400.9564062510{,}000 \to 10{,}500 \to 11{,}025 \to 11{,}576.25 \to 12{,}155.0625 \to 12{,}762.815625 \to 13{,}400.95640625. …

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