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Example · Example 10

Q.A weak monobasic acid HA\text{HA} has Ka=1.8×10−5K_a = 1.8 \times 10^{-5}. Using Ostwald's dilution law, calculate its degree of ionization α\alpha in a 0.1 M0.1\ \text{M} solution.

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By Ostwald's dilution law, α≈Ka/C=1.8×10−5/0.1=1.8×10−4\alpha \approx \sqrt{K_a/C} = \sqrt{1.8\times10^{-5}/0.1} = \sqrt{1.8 \times 10^{-4}}. Since 1.8≈1.342\sqrt{1.8} \approx 1.342, α≈1.342×10−2=0.01342\alpha \approx 1.342 \times 10^{-2} = 0.01342. [!ANSWER] $\alpha \approx …

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