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Exercise · Q20

Q.Distinguish between qpq_p (heat exchanged at constant pressure) and qvq_v (heat exchanged at constant volume). Starting from H=U+PVH = U + PV, derive the relation ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT for a reaction carried out at constant temperature involving gases.

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qvq_v is the heat exchanged by a system at constant volume — since no volume change means no PVPV-work is done (w=0w=0), the First Law gives ΔU=qv+0=qv\Delta U = q_v + 0 = q_v, so heat exchanged at constant volume equals ΔU\Delta U directly. qpq_p is the heat exchanged at constant pressure — here the system typically does expand or contract, so some of the heat exchanged goes into (or comes from) PVPV-work; it can be shown that qp=ΔHq_p = \Delta H. \n\nDerivation: Starting from the definition H=U+PVH = U + PV, for a change at constant temperature and pressure, ΔH=ΔU+PΔV+VΔP\Delta H = \Delta U + P\Delta V + V\Delta P. Since pressure is constant, ΔP=0\Delta P = 0, so this simplifies to ΔH=ΔU+PΔV\Delta H = \Delta U + P\Delta V. For a reaction involving only ideal gases at constant temperature, the ideal gas law gives PV=ngRTPV = n_gRT, so PΔV=Δ(PV)=Δng⋅RTP\Delta V = \Delta(PV) = \Delta n_g \cdot RT (since RR and TT are both constant, only ngn_g, the moles of gas, changes across the reaction). S …

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