Skip to content
Exercise · Q28

Q.Predict, with a brief reason, the sign of the entropy change (ΔS\Delta S) for each of the following processes:

(a) melting of ice at 273 K273\ \text{K},
(b) compression of a gas at constant temperature,
(c) 2H2(g)+O2(g)→2H2O(l)2\text{H}_2(g) + \text{O}_2(g) \rightarrow 2\text{H}_2\text{O}(l).
West Bengal WbchseTextbookSubjectiveImportance★★★★★
93% · 28/30 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

(a) Melting of ice at 273 K273\ \text{K}: ΔS>0\Delta S > 0. The rigid, highly ordered crystalline lattice of ice, with each water molecule locked into a fixed position, transforms into the far more disordered, mobile arrangement of liquid water, in which molecules can move relatively freely past one another — a substantial increase in the number of accessible microscopic arrangements. (b) Compression of a gas at constant temperature: ΔS<0\Delta S < 0. Compressing a gas confines its molecules to a smaller volume, reducing the number of possible positions (spatial microstates) available to them, so the gas becomes more ordered and its entropy decreases — the direct converse of the isothermal expansion case, where ΔS=nRln⁡(V2/V1)\Delta S = nR\ln(V_2/V_1) becomes negative when V2<V1V_2 < V_1. (c) 2H2(g)+O2(g)→2H2O(l)2\text{H}_2(g) + \text{O}_2(g) \rightarrow 2\text{H}_2\text{O}(l): ΔS<0\Delta S < 0. T …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.