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Example · Example 4

Q.Find the coefficient of x5x^5 in the expansion of (x+3)8(x+3)^8.

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The general term of (x+3)8(x+3)^8 is Tr+1=8Cr x8−r 3rT_{r+1}={}^{8}C_r\,x^{8-r}\,3^r. Setting the power of xx equal to 55: 8−r=5⇒r=38-r=5 \Rightarrow r=3. So the term containing x5x^5 is T4=8C3 x5 33T_4={}^{8}C_3\,x^5\,3^3. Since 8C3=8!3! 5!=56^{8}C_3=\dfrac{8!}{3!\,5!}=56 …

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