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Exercise: General Term · Q17

Q.Find the term independent of xx in the expansion of (x−2x2)9\left(x-\dfrac{2}{x^2}\right)^9.

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The general term of (x−2x2)9\left(x-\dfrac{2}{x^2}\right)^9 is Tr+1=9Cr x9−r(−2x2)r=9Cr(−2)r x9−r−2r=9Cr(−2)r x9−3rT_{r+1}={}^{9}C_r\,x^{9-r}\left(-\dfrac{2}{x^2}\right)^r={}^{9}C_r(-2)^r\,x^{9-r-2r}={}^{9}C_r(-2)^r\,x^{9-3r}. The term independent of xx has exponent 00: 9−3r=0⇒r=39-3r=0\Rightarrow r=3. So the term is 9C3(−2)3^{9}C_3(-2)^3. Since $^{9}C_ …

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