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Exercise: General Term · Q15

Q.Find the 77th term in the expansion of (3x−y)10(3x-y)^{10}.

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For (3x−y)10(3x-y)^{10}, the general term is Tr+1=10Cr(3x)10−r(−y)rT_{r+1}={}^{10}C_r(3x)^{10-r}(-y)^r. The 77th term is T7=T6+1T_7=T_{6+1}, so r=6r=6: T7=10C6(3x)4(−y)6T_7={}^{10}C_6(3x)^{4}(-y)^6. Since 66 is even, (−y)6=y6(-y)^6=y^6. Now 10C6=10C4=210^{10}C_6={}^{10}C_4=210 and (3x)4=81x4(3x)^4=81x^4, so T7=210×81x4y6=17010x4y6T_7=210\times81x^4y^6=17010x^4y^6. [!ANSWER] T7=17010x4y6T_7=17010x^4y^6.

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