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Q.Find the value of r, if the coefficients of (2r+4)-th and (r-2)-th terms in the expansion of (1+x)^18 are equal.

West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 2mImportance★★★★★est
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Equating the coefficients of the (2r+4)(2r+4)-th and (r−2)(r-2)-th terms of (1+x)18(1+x)^{18} using 18Ck^{18}C_k symmetry gives r=6r=6.

The kk-th term of (1+x)18(1+x)^{18} is Tk= 18Ck−1 xk−1T_k=\,^{18}C_{k-1}\,x^{k-1}, so its coefficient is 18Ck−1^{18}C_{k-1}.

Coefficient of the (2r+4)(2r+4)-th term: 18C2r+3^{18}C_{2r+3}.

Coefficient of the (r−2)(r-2)-th term: 18Cr−3^{18}C_{r-3}.

Setting them equal: 18C2r+3= 18Cr−3^{18}C_{2r+3}=\,^{18}C_{r-3}.

By the property 18Cp= 18Cq  ⟺  p=q^{18}C_p=\,^{18}C_q\iff p=q or p+q=18p+q=18:

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